3
2
−
32−
+ SO
3
Chemistry, 26.03.2020 01:11 taylorlindsey9329
IO
3
2
−
32−
+ SO
3
2
+
32+
→ I +SO
4
2
−
42−
The oxidation state of oxygen in the product's equation is
Answers: 1
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You know the right answer?
IO
3
2
−
32−
+ SO
3
3
2
−
32−
+ SO
3
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