The 1H NMR spectrum of compound A (C15H14O) shows only two signals: a multiplet at 7.15 ppm and a singlet at 3.55 ppm in a 5:2 ratio. The IR spectrum has no absorption in the 3200–4000 cm–1 region, but strong peaks can be found near 1700 cm–1. Compound A reacts with NaBH4 followed by acidification to give compound B of the molecular formula C15H16O. The reaction of A with CH3MgBr, and then with H3O+, gives C, with a molecular formula of C16H18O. Suggest structures for B and C.