If the specific heat capacity of sliver metal is 0.057 j/gc and if 55.00g of the metal absorbs 47.3 j oh heat how much does the temperature rise?

The temperature of silver metal rises by 15.087°C.

Explanation:

Given,

mass = 55 grams

Heat (Q) = 47.3 Joules

Specific heat capacity = 0.057 J/g°C

The temperature rise of the silver metal can be found by using the formula,

Q = (mass) (ΔT) (Cp)

Where ΔT is the rise in temperature.

Substituting the values,

47.3 = (55)(ΔT)(0.057)

Solving, we get,

ΔT = 15.087°C.

Therefore, temperature of silver metal rises by 15.087°C.

u i forgot the answer?

i would say b

explanation:

but i think i would need more information than that