The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) +
502 (g) → 3C02 (g) + 4H2O The reaction of 10 mol of O2 will produce how many moles of H2O?

8 moles of H2O

Explanation:

C3H8 (g) + 502 (g) → 3C02 (g) + 4H2O

Propane + Oxygen → Carbon dioxide + water

In the reaction above,

5 moles of O2 produce 4 moles of H2O

10 mol of O2 will produce Z moles of H2O

To get the value of Z, cross multiply

Z moles x 5 moles = 4 moles x 10 moles 5Z = 40

Z = 40/5

Z = 8

Therefore, the equation becomes

2C3H8 (g) + 1002 (g) → 6C02 (g) + 8H2O

Thus, 10 moles of O2 will produce 8 moles of H2O

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.