The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 1.0 mol of O2 will produce mol of H2O.

0.8 moles of H2O

Explanation:

C3H8 (g) + 502 (g) → 3C02 (g) + 4H2O(g)

Propane + Oxygen → Carbon dioxide + water

In the reaction above,

5 moles of O2 produce 4 moles of H2O

1.0 mol of O2 will produce Z moles of H2O

To get the value of Z, cross multiply

Z moles x 5 moles = 4 moles x 1.0 moles 5Z = 4

Z = 4/5

Z = 0.8

Thus, 1.0 moles of O2 will produce 0.8 moles of H2O

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