3.0 moles of silver chloride is dissolved in enough water to make a 2.0 liter solution

The given question is incomplete. The complete question is :

What is the molarity of a solution containing 3.0 moles of silver chloride dissolved in enough water to make 2.0 liter solution.

Molarity of a solution containing 3.0 moles of silver chloride dissolved in enough water to make 2.0 liter solutuion is 1.5 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

where,

n= moles of solute (silver chloride)  = 3.0

= volume of solution in L= 2.0 L

Putting in the values we get:

Thus molarity of a solution containing 3.0 moles of silver chloride dissolved in enough water to make 2.0 liter solutuion is 1.5 M

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole