In a titration of 50 ML of 0.20m NaOH is used to neutralize 10.0 ML of HCL. Calculate the molarity of the acid

1M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

NaOH + HCl —> NaCl + H2O

From the equation above,

nA (mole of acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of base) = 50mL

Mb (Molarity of base) = 0.2M

Va (volume of acid) = 10mL

Ma (Molarity of acid) =?

Using MaVa/MbVb = nA/nB, we can calculate the molarity of the acid as follow:

Ma x 10/0.2 x 50 = 1

Cross multiply to express in linear form

Ma x 10 = 0.2 x 50

Divide both side by 10

Ma = (0.2 x 50)/10

Ma = 1M

The molarity of the acid is 1M

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-