How much carbon dioxide is formed from 24.8 g of carbonic acid?

Mass = 17.6 g

Explanation:

Given data:

Mass of carbonic acid =24.8 g

Mass of carbon dioxide form = ?

Solution:

Chemical  equation:

H₂CO₃   →  CO₂ + H₂O

Number of moles of carbonic acid:

Number of moles = mass/ molar mass

Number of moles = 24.8 g / 62.03 g/mol

Number of moles = 0.4

Now we will compare the moles of CO₂ with H₂CO₃.

                          H₂CO₃      :          CO₂

                              1           :             1

                           0.4          :          0.4

Mass of CO₂ :

Mass = number of moles × molar mass

Mass = 0.4 mol × 44 g/mol

Mass = 17.6 g

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

2b2t

explanation:

2b2t