A student placed 15.0 gg of glucose (C6H12O6C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mLmL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 60.0 mLmL sample of this glucose solution was diluted to 0.500 LL. How many grams of glucose are in 100. mLmL of the final solution?

1.80 g

Explanation:

A student placed 15.0 g of glucose (C₆H₁₂O₆) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached.

The initial concentration of glucose is:

C₁ = 15.0 g/100 mL = 0.150 g/mL

A 60.0 mL sample of this glucose solution was diluted to 0.500 L (500 mL).

We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.150 g/mL × 60.0 mL / 500 mL

C₂ = 0.0180 g/mL

We can find the mass of glucose in 100 mL of the 0.0180 g/mL solution.

100 mL × 0.0180 g/mL = 1.80 g

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

the answer is c i believe