For the oxidation of glucose C6 H12 O6 + 602 -- 6H2O + 6C02, How many moles of oxygen will it take to consume 3.9 moles of glucose C6 H12 O6?
27
.12
.65
23.4

The answer to your question is 23.4 moles of Glucose

Explanation:

Data

moles of Oxygen = ?

moles of glucose = 3.9

-Balanced chemical reaction

           1C₆H₁₂O₆  +  6O₂   ⇒   6H₂O  +  6CO₂

Process

1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.

           1 mol of C₆H₁₂O₆ 6 moles of O₂

    3.9 moles of C₆H₁₂O₆   x

                                  x = (3.9 x 6 ) / 1

                                  x = 23.4 moles

2.- Conclusion

3.9 moles of glucose consume 23.4 moles of oxygen

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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