If a compound contain 40% sulphur and 59% oxygen ,find its empirical formula.

SO3

Explanation:

Data obtained from the question include:

S = 40%

O = 59%

To obtain the empirical formula, do the following:

Divide the above by their molar mass as shown below:

S = 40/32 = 1.25

O = 59/16 = 3.69

Next, divide by the smallest as shown below:

S = 1.25/125 = 1

O = 3.69/1.25 = 3

Therefore, the empirical formula is SO3

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