How many grams of HBr would exactly react with 2g of propene?

3.84 g HBr

Explanation:

A reaction between Propene and HBr is given by the equation;

HBr + C₃H₆ → C₃H₇Br

Note; this is an addition reaction where hydrogen halides are added to an alkene.

We are given 2 g of propene

Required to determine the mass of HBr used;

We first determine the number of moles of propene used

Moles = Mass ÷ molar mass

Molar mass of propene = 42.08 g/mol

Therefore;

Moles of propene = 2 g ÷ 42.08 g/mol

                               = 0.0475 moles

Then, from the equation, 1 mole of HBr reacts with 1 mole of propene

Thus;

Moles of HBr = Moles of propene

Moles of HBr = 0.0475 moles

Lastly, we determine the mass of HBr

Mass = Moles × Molar mass

Molar mass of HBr = 80.91 g/mol

Therefore;

Mass of HBr = 0.0475 moles × 80.91 g/mol

                     = 3.84 g

pure substance: iron,copper

impure substance: water,charcoal

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.