Chemistry, 27.03.2020 19:50 koranbutterton

The Earth rotates on it's axis in a counterclockwise direction once every 24 hours, deflecting anything travelling long distances on or above the surface. This is known a the Coriolis Effect. What impact could the Coriolis Effect have on weather patterns?

A) Chance of dense fog
B) chance of a cyclone
C) chance of a tsunami
D) chance of high speed winds

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Answer from: Tanya120

The Coriolis Effect could have chance of high speed winds on weather patterns.

Option: D

Explanation:

Coriolis effect is zero at equator and maximum at the poles due to the spherical shape of the earth. Due to this force all the moving agents like ocean currents, winds changes its way from its normal path and deflect towards right side in the northern hemisphere and left side in the southern hemisphere.

Coriolis effect is related with Ferell's law. Coriolis effect creates the power and by maintaining the law moving agents change its direction in both the hemisphere. The speed of prevailing winds increase due to coriolis effect.

Answer from: shiny9362

Explanation:

I had it on USA testprep hope this helps

Answer from: Quest

a corroding iron, if that's one of your choices

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

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