A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the gas changes to 4 atm?

The answer for the following problem is mentioned below.

Explanation:

Given:

Initial pressure of the gas () = 1.8 atm

Final pressure of the gas ()  = 4 atm

Initial temperature of the gas () = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas ()

We know;

From the ideal gas equation;

we know;

P  × V = n × R × T

So;

we can tell from the above equation;

    P ∝ T

(i.e.)

      = constant

        =

Where;

 = initial pressure of a gas

= final pressure of a gas

= initial temperature of a gas

= final temperature of a gas

        =

    =

    = 740 K

Therefore the final temperature of the gas is 740 K