Given the balanced neutralization equation from part B, how many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)? Assume that the sulfuric acid completely dissociates in water.

9 moles of KOH

Explanation:

Let's begin with the neutralization reaction.

Neutralization reaction always gives as product, water and a salt

2KOH + H₂SO₄ → 2H₂O + K₂SO₄

Ratio in the reactant side is 1:2. We can determine this rule of three:

1 mol of sulfuric acid can react with 2 moles of potassium hydroxide

Therefore, 4.5 moles sulfuric acod wil react with (4.5 . 2) /1 = 9 moles of KOH

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

they are both synthetic elements

explanation:

d