I need to find the new pressure. I got 129.9 kPa for my answer but I would like for someone to double check.

The new pressure is 129.9 kPa.

Explanation:

Step 1: Data given

The initial pressure is 120 kPa

The initial temperature = 30.0 °C = 273 + 30 = 303 K

The temperature increases to 55 °C = 328 K

Step 2: Calculate the new pressure

P1/T1 = P2/T2

⇒with P1 = the initial pressure P1 = 120 kPa

⇒with T1 = the initial temperature = 30.0 °C = 303 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with T2 = the increased temperature = 55 °C = 328 K

120 kPa / 303 K = P2 / 328 K

P2 = (120 kPa / 303K) *328 K

P2 = 129.9 kPa

The new pressure is 129.9 kPa. Your answer was correct.

the answer to this question is 3.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.