A helium balloon can hold about 6.8mol of the gas. Assuming the balloon is kept at room temperature (25°C) and has a maximum volume of 1.2 liters, what is the pressure inside the balloon?

P = 138.64 atm

Explanation:

Given data:

Volume of helium = 1.2 L

Number of moles = 6.8 mol

Temperature = 25°C (25+273 = 298 K)

Pressure of gas = ?

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

P = nRT/V

P = 6.8 mol ×  0.0821 atm.L/ mol.K  × 298 K / 1.2 L

P = 166.4 atm / 1.2

P = 138.64 atm

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