What would be the volume of 0.500 mole of an ideal gas at a temperature of 273.15 Kelvins and 1 atm?

V = 11.21 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.500 mol

Temperature = 273.15 K

Pressure of gas = 1 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.500 mol ×  0.0821 atm.L/ mol.K  × 273.15 K / 1 atm

V = 11.21 L / 1

V = 11.21 L

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