For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.

(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e. g, ABC.)

1. lead fluoride (answer here )
2. aluminum hydroxide (answer here )
A. Mg(OH)2
B. BaF2
C. Ag3PO4
D. AgI

Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.

lead fluoride

aluminum hydroxide

Ksp =

Ksp =

Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴

Explanation:

The expression for the solubility product can be written as the product of the concentration of the ions present in the solution.

PbF₂ → Pb²⁺ + 2 F⁻

Then the Ksp can be written as,

Ksp = [ Pb²⁺] [F⁻]²

If the concentration can be considered as s, then the Ksp can be written as,

Ksp = s× s² = s³

For Aluminum hydroxide on dissociation it gives 4 ions as,

Al(OH)₃ → Al³⁺ + 3 OH⁻

Ksp = [Al³⁺] [OH⁻]³

      = s × s³ = s⁴

Thus,For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.