I can’t figure out the answers.

Explanation:

1)

Given data:

Moles of Al(OH)₃ = 0.52 mol

Moles of HCl consume = ?

Solution:

Chemical equation:

Al(OH)₃ + 3HCl      →     AlCl₃ + 3H₂O

Now we will compare the moles of HCl and Al(OH)₃.

                        Al(OH)₃         :           HCl

                            1                 :             3

                          0.52            :             3×0.52 = 1.56 mol

1.56 moles of HCl are consumed with 0.52 moles of  Al(OH)₃ .

2)

Given data:

Moles of water  produced = ?

Moles of Al(OH)₃ react = 1.35 mol

Solution:

Chemical equation:

Al(OH)₃ + 3HCl      →     AlCl₃ + 3H₂O

Now we will compare the moles of H₂O and Al(OH)₃.

                        Al(OH)₃         :          H₂O

                            1                 :             3

                          1.35              :             3×1.35 = 4.05 mol

4.05 moles of H₂O are produced from 1.35 moles of  Al(OH)₃ .

3)

Given data:

Moles of water  produced = ?

Moles of HCl react = 1.98 mol

Solution:

Chemical equation:

Al(OH)₃ + 3HCl      →     AlCl₃ + 3H₂O

Now we will compare the moles of H₂O and HCl.

                             HCl           :          H₂O

                              3              :             3

                            1.98           :             1.98

1.98 moles of H₂O are produced from 1.98 moles of  HCl.

4)

Given data:

Moles of Al(OH)₃ required = ?

Moles of HCl react = 65 mol

Solution:

Chemical equation:

Al(OH)₃ + 3HCl      →     AlCl₃ + 3H₂O

Now we will compare the moles of HCl  and Al(OH)₃.

                             HCl           :           Al(OH)₃

                              3              :               1

                             65             :            1/3×65 = 21.67 mol

65 moles of HCl  react with 21.67 moles of Al(OH)₃.

5)

Given data:

Moles of iron produced = 5.61 mol

Moles of CO required = ?

Solution:

Chemical equation:

Fe₂O₃  + 3 CO  →     2Fe  + 3CO₂

Now we will compare the moles of iron and CO.

                          Fe         :        CO

                           2          :         3

                          5.61       :     3/2×5.61 = 8.4 mol

For the production of 5.61 moles of Fe 8.4 moles of Co are required.

6)

Given data:

Moles of CO react = 16.8 mol

Moles of Fe₂O₃ required = ?

Solution:

Chemical equation:

Fe₂O₃  + 3 CO  →     2Fe  + 3CO₂

Now we will compare the moles of Fe₂O₃  and CO.

                          CO         :       Fe₂O₃

                             3          :          1

                          16.8         :     1/3×16.8= 5.6 mol

5.6 moles of Fe₂O₃  required to react with 16.8 moles of CO.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

that's what i got you can count the number of atoms