How much heat is added if 0.2706g of water increases in temperature by 0.216 degree C?

0.25J

Explanation:

Given parameters:

Mass of water  = 0.2706g

temperature change  = 0.216°C

Unknown:

Amount of heat added  = ?

Solution:

The quantity of heat added to a substance is given by the expression below;

               H  = m c Δt

where m is the mass of the body

           c is the specific heat capacity

           Δt is the temperature change

specific heat capacity is a constant and for water the value is 4.2J/g°C

    Input the variables to solve for H;

                  H  = 0.2706 x 4.2 x 0.216   = 0.25J

i think its 5049.

i hope this !