A sample of carbon monoxide gas has a volume of
3.45 L and a pressure of 2.82 atm, under a
constant temperature of 28 "C. What is the new
volume, if the pressure is increased to 4.2 atm?

2.3L

Explanation:

Given that:

Volume of carbon monoxide gas V1 = 3.45L

Temperature T1 = 28°C

Convert Celsius to Kelvin

(28°C + 273 = 301K)

Pressure P1 = 2.82 atm

Final Volume V2 = ?

Final temperature T2 = 28°C = 301K

Final pressure = 4.2atm

Then, apply the general gas equation

(P1V1)/T1 = (P2V2)/T2

(2.82 x 3.45)/301 = (4.2 x V2)/301

9.73/301 = 4.2V2/301

0.032 = 0.014V2

To get the value of V2, divide both sides by 0.014

0.032/0.014 = 0.014V2/0.014

2.286 = V2

Rounded to nearest tenth, V2 becomes 2.3L

Thus, the new volume of the carbon monoxide gas is 2.3 liters