Problem PageQuestion A major component of gasoline is octane . When octane is burned in air, it chemically reacts with oxygen gas to produce carbon dioxide and water . What mass of oxygen gas is consumed by the reaction of 6.1 g of octane

grams of oxygen = 21.40 g

Explanation:

octane → C8H18

The chemical reaction needs to be represented with a chemical equation before solving. The equation also need to be balanced.

C8H18 + O2 → CO2 + H2O

Balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Molar mass of octane = 12 × 8 + 18 = 96 + 18 = 114 g

Mass of octane in the chemical equation = 2 (114) = 228 g

molar mass of oxygen = 32 g

mass of oxygen in the chemical equation = 25 × 32 = 800  g

if  228 g of octane react with 800 g of oxygen

6.1 g of octane will require ? grams of oxygen

cross multiply

grams of oxygen = 6.1 × 800/228

grams of oxygen = 4880 /228

grams of oxygen = 21.4035087719

grams of oxygen = 21.40 g

most likely he is cheating on you

law of conservation of matter