) Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = k [X][Y]2 A) The rate of reaction will increase by a factor of 2. B) The rate of reaction will increase by a factor of 5. C) The rate of reaction will increase by a factor of 4. D) The rate of reaction will decrease by a factor of 2. E) The rate of reaction will remain unchanged.

The correct answer is option C.

Explanation:

The given rate law of reaction :

Rate of the reaction after doubling the concentration of Y : R'

The rate of the reaction will increase by the factor of 4.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.