In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of water. 8.20 mL of 0.051 M NaOH was required to reach the endpoint. Remembering that the acid in wine is tartaric acid, a diprotic acid, what is the molarity (M/L) of tartaric acid in this sample of wine

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is tartaric acid

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

0.0042 M is the molarity of tartaric acid in this sample of wine.

b

explanation:

mitosis

the answer is 0.42 is that is an option. this question provides no info