For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities. (If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e. G, ABC.) 1. lead fluoride A. Mg(OH)2 2. aluminum hydroxide B. BaF2 C. Ag3PO4 D. AgI Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water. lead fluoride aluminum hydroxide Ksp = Ksp = Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

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i just learnt this recently but i need to look through my notes again

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

it is b that is the answer.