6. A 0.1310 g sample of an unknown diprotic acid is diluted to 100.00 mL and titrated by using 0.1910 M NaOH. If 14.20 mL of the NaOH solution is required to reach the second equivalence point, what is the molar mass of the acid?

Explanation:

Hello,

In this case, it is more convenient to define this titration in terms of normality:

In such a way, the normality of the acid, considering the normality of sodium hydroxide equals its molarity (one hydroxile in its structure) is:

Thus, the moles are:

Hence, the molar mass:

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