The Ksp of barium fluoride, BaF2, is 1.6 x 10-6. A solution of 5.0M NaF is added dropwise to a 2.0L solution that is 0.016 M in Ba2+. When the concentration of fluoride ion exceeds M, BaF2 will precipitate. What volume (in mL) of NaF must be added to cause BaF2 to precipitate? mL

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

4 mL volume of NaF must be added to cause to precipitate.

Explanation:

Concentration of barium ions =

Volume of barium ion solution = 2.0 L

The solubility product of the barium fluoride =

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

Concentration of fluoride ion =

Volume of solution =

Concentration of NaF solution added =

Volume of NaF solution added =

1 L = 1000 mL

0.004 L = 0.004 × 1000 mL = 4 mL

4 mL volume of NaF must be added to cause to precipitate.

explanation:

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