Determine the limiting reactant in a mixture containing 139 g of Se, 431 g of Cl2, and 110 g of H2O. Calculate the maximum mass (in grams) of selenic acid, H2SeO4, that can be produced in the reaction.

Answer : The limiting reagent is

The mass of produced is, 220.4 grams.

Explanation : Given,

Mass of Se = 139 g

Mass of = 431 g

Mass of = 110 g

Molar mass of Se = 79 g/mol

Molar mass of = 71 g/mol

Molar mass of = 18 g/mol

First we have to calculate the moles of Se, and .

and,

and,

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

From the balanced reaction we conclude that:

As, 4 mole of react with 1 mole of

So, 6.11 moles of react with moles of

and,

As, 4 mole of react with 3 mole of

So, 6.11 moles of react with moles of

From this we conclude that, are excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 4 mole of react to give 1 mole of

So, 6.11 mole of react to give mole of

Now we have to calculate the mass of

Molar mass of = 145 g/mole

Therefore, the mass of produced is, 220.4 grams.

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