Aqueous hydrobromic acid will react with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . Suppose 17. g of hydrobromic acid is mixed with 2.44 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

The mass of NaBr that can be produced is 6.3 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of HBr = 17 g

Molar mass of HBr = 81 g/mol

Putting values in equation 1, we get:

Given mass of NaOH = 2.44 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of HBr and NaOH follows:

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HBr

So, 0.061 moles of NaOH will react with = of HBr

As, given amount of HBr is more than the required amount. So, it is considered as an excess reagent.

Thus, NaOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of NaOH produces 1 mole of NaBr

So, 0.061 moles of NaOH will produce = of carbon dioxide

Now, calculating the mass of NaBr from equation 1, we get:

Molar mass of NaBr = 103 g/mol

Moles of NaBr = 0.061 moles

Putting values in equation 1, we get:

Hence, the mass of NaBr that can be produced is 6.3 grams

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