At a certain temperature, the K p for the decomposition of H 2 S is 0.743 . H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g ) Initially, only H 2 S is present at a pressure of 0.298 atm in a closed container. What is the total pressure in the container at equilibrium?

The total pressure in the container at equilibrium is 0.526 atm

Explanation:

Equilibrium constant for a reaction is the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

For the given reaction:

initilal:    0.298 atm            0        0

at eqm    (0.298-x) atm     x atm    x atm

Total pressure  at eqm = (0.298-x) + x + x = 0.298 + x

Equilibrium constant is given as:

Thus (0.298 + x) = (0.298+0.228) atm = 0.526 atm

The total pressure in the container at equilibrium is 0.526 atm

h let me think

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.