A chemist prepares a solution of ironIII chloride FeCl3 by measuring out 72.7mg of FeCl3 into a 100.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution.

The molarity of chloride anions in the solution is 0.01344 M

Explanation:

To calculate the molarity of solution, we use the equation:

Given mass of ferric chloride = 72.7 mg = 0.0727 g    (Conversion factor:  1 g = 1000 mg)

Molar mass of ferric chloride = 162.2 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:

1 mole of ferric chloride contains 1 mole of ions and 3 moles of ions

Moles of = (3 × 0.00448) = 0.01344 M

Hence, the molarity of chloride anions in the solution is 0.01344 M

2b2t

explanation:

2b2t

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.