What mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution?

We have that for the Question "" it can be said that the  mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution is

W=378.5gram

From the question we are told

What mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution?

Generally the equation for the water needed  is mathematically given as

Therefore

The  mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution is

W=5.5 +378

W=378.5grams

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383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.

Explanation:

Given that:

Solution to be prepared is 5.5 %

mass of KCl is 22 gram

mass of water required =?

5.5 % solution means that

5.5 grams in 100 ml or gram of water to make solution.

let the water required is 5.5 + x, so the equation will be

5.5 = x 100

121+ 5.5x = 2200

5.5 x = 2200-121

     x =

    x = 378 grams

The mass of water added to KCl to make it 5.5% percent solution is

5.5 +378

= 383.5 grams.

to make the solution of 5.5 percent of KCl weighing 22 grams.

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