• 8. When calcium carbonate is heated, it produces calcium oxide and carbon dioxide. The equation for the reaction is CaCO3 (s) → CaO(s) + CO2 (g). How many grams of calcium carbonate (molar mass = 100.09 g/mol) must be decomposed to produce 5.00 L of carbon dioxide at STP?

m=9

step-by-step explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

i do not get it   at all

level 4 to level 2 : ))