Chemistry, 31.03.2020 03:21 cathydaves
The compound carbon suboxide, C3O2, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide. (Data: 2CO(g) + C(s) → C3O2(g) ΔH° = 127.3 kJ/mol and: ΔHf° of CO(g) = –110.5 kJ/mol)
Answers: 3
is -92.7 kJ/mol![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]](/tpl/images/0572/6547/72c39.png)
![\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(C_3O_2(g))})]-[(2\times \Delta H^o_f_{(CO(g))})+(1\times \Delta H^o_f_{(C(s))})]](/tpl/images/0572/6547/3be78.png)
![127.3=[(1\times \Delta H^o_f_{(C_3O_2(g))})]-[(2\times (-110))+(1\times (0))]\\\\\Delta H^o_f_{(C_3O_2(g))}=-92.7kJ/mol](/tpl/images/0572/6547/5dacc.png)
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The compound carbon suboxide, C3O2, is a gas at room temperature. Use the data supplied to calculate...
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