Okay, so we had a chemistry lab on titrating an unknown weak acid into a known solution of a strong base (NaOH). This means, we slowly dripped around 10 mL of weak acid into the strong base solution. For a presentation, I'm asked for what would happen if we reversed this- as in, what would happen if instead, we dripped 10 mL of NaOH into a solution of the unknown weak acid.

Here's the exact question, What would be different about the weak acid titration if you were to put the unknown weak acid in the buret and titrate 10 mL of a known molarity NaOH solution? How would the titration curve be different?

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.