PLEASE HELP!! I have to pass this class! Anything!!

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2

Explanation:

Step 1: data given

Number of moles Fe2O3 = 12.0 moles

Number of moles CO = 12.0 moles

Step 2: The balanced equation

3Fe2O3 +CO → 2Fe3O4 + CO2

Step 3: Calculate the limiting reactant

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

Fe2O3 is the limiting reactant. It will completely be consumed (12.0 moles).

CO is in excess. There will react 12.0 / 3 = 4.0 moles

There will remain 12.0 - 4.0 = 8.0 moles

Step 4: Calculate moles products

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

For 12.0 moles Fe2O3 we'll have 2/3 * 12.0 = 8.0 moles Fe3O4

For 12.0 moles Fe2O3 we'll have 12.0 / 3 = 4.0 moles CO2

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2

i dont know

explanation:

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.