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We'll have 82 moles ZnO and 41 moles S

Explanation:

Step 1: data given

Number of moles Zinc (Zn) = 82 moles

Number of moles sulfur oxide (SO2) = 42 moles

Step 2: The balanced equation

2Zn + SO2 → 2ZnO + S

Step 3: Calculate the limiting reactant

For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur

Zinc is the limiting reactant. It will completely be consume (82 moles). Sulfur oxide is in excess. There will react 82/2 = 41 moles

There will remain 42-41 = 1 mol SO2

Step 4: Calculate moles of products

For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur

For 82 moles Zinc we'll have 82 moles of Zinc Oxide (ZnO)

For 82 moles Zinc we'll have 82/2 = 41 moles of sulfur

We'll have 82 moles ZnO and 41 moles S

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890