What's the difference between a word equation and a formula equation?

a, Word Equations give quantitative information about the reaction

b ,Word equations give qualitative information about the reaction.

c, word equations and formula equations are the same

b ,Word equations give qualitative information about the reaction.

Explanation:

Word equation can give only qualitative information about reactants and products. While formula equation gives quantitative information about reactant and products.

For example:

Photosynthesis reaction:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Word equation:

Carbon dioxide + water  →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sugar and oxygen are formed. This equation only provide the qualitative data which type of reactants and product are present.

Formula equation:

6H₂O + 6CO₂  →   C₆H₁₂O₆ + 6O₂

water and carbon dioxide react to form sugar and oxygen.

it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water and created one mole of glucose and six mole of oxygen.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

beta decay is the answer