How many grams of water can be produced when 8.73 moles of benzene (c6h6) react with excess oxygen? . unbalanced equation: c6h6 + o2 → co2 + h2o. show your solution.

2 C6H6 + 15 O2 = 12 CO2 + 6 H2O

2 moles C6H6 6 moles H2O
8.73 moles C6H6 ( moles H2O)

( moles H2O) = 8.73 x 6 / 2

( moles H2O) = 52.38 / 2

= 26.19 moles of H2O

Molar mass H2O = 18.00 g/mol

1 mole 18.00 g
26.19 moles ( mass of H2O)

mass of H2O = 26. 19 x 18.00 => 471.42 g of water

hope this helps!

Exothermic,  physical change after it is already baked