Calculate the molarity of 7.8 moles of MgCl2 in 3.6 L of solution. Report your answer with 3
decimal places

The molarity of the solution is: 2,167 M.

Explanation:

Molarity is a concentration measure that expresses the moles of solute per liter of solution. In this case it is calculated with the simple rule of three:

3,6 L solution 7,8 moles of MgCl2

1 L solution   x= (1 L solution x 7,8 moles of MgCl2)/3,6 L solution

x=2,167 moles of MgCl2 ---> The solution is 2, 167 M

dynamic equilibrium is the answer.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.