Exactly 5.00 L of air at -50.0 °C is warmed to 100.0 °C. What is the new volume if the pressure remains constant?

V₂ = 8.36 L

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = -50.0°C (-50 + 273 = 223 k)

Final temperature = 100°C (100+273 = 373 k)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 5.00 L × 373 K / 223 K

V₂ = 1865 L.K / 223 K

V₂ = 8.36 L