What is the mole fraction of LiCl in a mixture of 0.564 g NaCl, 1.52 f KCl and 0.857 g LiCl?

Molar Mass
NaCl: 58.44 g/mol
KCl: 74.55 g/mol
LiCl: 42.39 g/mol

Mole fraction of LiCl = 0.4

Explanation:

Given data:

Mass of NaCl = 0.564 g

Mass of KCl = 1.52 g

Mass of LiCl = 0.857 g

Mole friction of LiCl = ?

Solution:

First of all we will calculate the moles of each compound.

Moles of NaCl:

Moles of NaCl = mass/ molar mass

Moles of NaCl = 0.564 g/ 58.44 g/mol

Moles of NaCl = 0.01 mol

Moles of KCl:

Moles of KCl = mass/ molar mass

Moles of KCl = 1.52 g/ 74.55 g/mol

Moles of KCl = 0.02 mol

Moles of LiCl:

Moles of LiCl = mass/ molar mass

Moles of LiCl = 0.857 g/ 42.39 g/mol

Moles of LiCl = 0.02 mol

Mole fraction of LiCl:

Mole fraction of LiCl = moles of LiCl / total moles of mixture

Total number of moles = 0.02+0.02+0.01 = 0.05

Mole fraction of LiCl = 0.02/0.05 = 0.4

the ratio of the conjugate base to the acid required to attain the desired ph.