It requires 0.0780L of a 0.12 M HCl solution to completely neutralize 0.0280L of an unknown LiOH solution. What is the concentration of the unknown LiOH solution?

C₂ = 0.334 M

Explanation:

Given data:

Volume of HCl  = 0.0780 L

Concentration of HCl = 0.12 M

Volume of LiOH = 0.0280 L

Concentration of LiOH = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Concentration of HCl

V₁ = Volume of HCl

C₂ = Concentration of LiOH

V₂ = Volume of LiOH

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.12 M × 0.0780 L =  C₂ × 0.0280 L

0.00936  M.L = C₂ × 0.0280 L

C₂ = 0.00936 M.L/0.0280 L

C₂ = 0.334 M

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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