A sample of 5 moles of gas is held at a constant temperature of 500 k inside a container with a volume of 0.25 l. What pressure in atmosphere is the gas under?

41 atmosphere

Explanation:

Given that:

Volume of water V = 0.5 L

(since 1 liter = 1dm3

0.5L = 0.5dm3)

Temperature T = 500K

Pressure P = ?

Number of moles of gas = 5 moles

Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 0.5dm3 = 5 moles x (0.0082 atm dm3 K-1 mol-1 x 500K)

p x 0.5dm3 = 20.5 atm dm3

p = (20.5 atm dm3 / 0.5dm3)

p = 41 atm

Thus, the gas is under a pressure of 41 atmosphere

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