A relatively simple way of estimating profit is to consider the the difference between the cost (the total spent on materials and waste disposal) and the earnings (the price at which the product can be sold).Calculate the profit from producing 55.00 kg of propene oxide.

( $ 8,384 )

Explanation:

-  From given information we know that 1 mol mCPHA provides the oxygens to 1 mol of propene, to make 1 mole of C3H6O so:

               1 mol C3H6      +     1 mol mCPHA      -->    1 mol C3H6O

              ( Mr = 42.08 g)        ( Mr = 172.57 g)          ( Mr = 58.08 g )

- For 1 kg equivalent equation by dividing the whole equation by the highest Molar Mass i.e of C3H6O, the result would be:

              1 mol C3H6      +     1 mol mCPHA      -->    1 mol C3H6O

            ( 42.08 / 58.08 )      ( 172.57 / 58.08 )          ( 1 )

     =     (  0.72452 kg )         ( 2.9712 kg )                  ( 1 kg )    

- However note that the reaction gives only a 96% yield, we scale up the reactants to get that desired 1 kg of C3H6O:

        (0.72452 kg ) (96/100)  + (2.9712 kg) (96/100)  --> 1 kg

     =      ( 0.75471 kg )            + ( 3.095 kg ) > 1 kg            

- The costs for each component produced:

            (0.75471 kg C3H6) ($10.97 per kg) = $8.279

            (3.095 kg mCPHA) ($5.28 per kg) = $16.342

            (0.75471 kg C3H6) / (0.0210 kg C3H6 / L dichloromethane) = 35.939

            (35.939 Litres dichloromethane) ($2.12 per L) = $ 76.19

- The cost of waste disposal ($5.00 per kilogram of propene oxide)  produced total cost, disregarding labor,energy, & facility costs:

     $8.279 + $16.342 + $ 76.19 + $5.00 = $105.81 per kg C3H6O produced

- Profit: ($258.25 / kg C3H6O) - ($105.81 cost per kg) = $152.44 profit /kg

- Calculate the profit from producing 55.00kg of propene oxide:

             (55.00kg) ($152.44 /kg) = $8,384.2 .. ( $ 8,384 )