At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa

The temperature in Celsius is 383, 7°C

Explanation:

We use the formula PV=nRT. We convert the pressure in KPa into atm:

101,325kPa---1 atm

114kPax=(114kPa x 1 atm)/101,325kPa=1, 125 atm

PV=nRT  ---> T= PV/nR

T=1, 125 atm x 35, 9 L/ 0,750 mol x 0,082 l atm/K mol

T= 656, 7 K

0°C= 273K---> 656,7 -273K= 383,7°C

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