Draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base.

CH3CH2COO^-

Explanation:

CH3CH2COOH + B^- > CH3CH2COO^- + BH

When a strong base reacts with propanoic acid, the only replaceable hydrogen atom in the compound is removed. Recall that carboxylic acids are often monobasic, hence the removal of that hydrogen creates a carboxylate ion whose structure has been shown in the answer section.

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