Calculate the number of moles of h2 produced from the reaction of 2.08 mil
Of Mg and 2.08 mil of HCL

The amount of hydrogen gas produced in the reaction is 1.04 moles

Explanation:

We are given:

Moles of Mg = 2.08 moles

Moles of HCl = 2.08 moles

The chemical equation for the reaction of magnesium and HCl follows:

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of magnesium metal.

So, 2.08 moles of HCl will react with = of magnesium metal.

As, given amount of magnesium metal is more than the required amount. So, it is considered as an excess reagent.

Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of HCl produces 1 mole of hydrogen gas

So, 2.08 moles of HCl will produce = of hydrogen gas

Hence, the amount of hydrogen gas produced in the reaction is 1.04 moles

10 years is the answer