What is the concentration of chloride ion when 16.8ml of a 0.554 M solution of barium chloride is combined with 16.8ml of a 0.593M of aluminum chloride?

The concentration of chloride ion is 2.887 M.

Explanation:

Here we have a combination BaCl₂  and AlCl₃

1 mole BaCl₂ can produce 2 moles chloride ions as follows;

BaCl₂ → Ba²⁺ + 2Cl⁻

Therefore;

0.554  mole BaCl₂ can produce 2×0.554  moles chloride ions;

1 mole AlCl₃ can produce 3 moles chloride ions as follows;

AlCl₃ → Al³⁺ + 3Cl⁻

Therefore;

0.593 mole AlCl₃ can produce 3×0.593 moles chloride ions

Total concentration of chloride ions = 2×0.554 + 3×0.593 = 2.887 moles of Cl⁻ in 2×16.8 ml solution

The concentration of Cl⁻ is 2.887 M

the answer is na (sodium)